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200x-x^2=40x+3375
We move all terms to the left:
200x-x^2-(40x+3375)=0
We add all the numbers together, and all the variables
-1x^2+200x-(40x+3375)=0
We get rid of parentheses
-1x^2+200x-40x-3375=0
We add all the numbers together, and all the variables
-1x^2+160x-3375=0
a = -1; b = 160; c = -3375;
Δ = b2-4ac
Δ = 1602-4·(-1)·(-3375)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-110}{2*-1}=\frac{-270}{-2} =+135 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+110}{2*-1}=\frac{-50}{-2} =+25 $
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